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Acceleration of Charge

  1. Jul 20, 2010 #1
    1. The problem statement, all variables and given/known data

    A dust particle with mass of 0.043g and a charge of 2.0 * 10^(-6)C is in a region of space where the potential is given by V(x) = (2.0V/m^2)x^2 - (3.0V/m^3)x^3. If the particle starts at x = 2.1m, what is the initial acceleration of the charge? Your explanation will be extremely helpful. Thank you for taking the time to look at this question.


    2. Relevant equations

    Vba = (Ub-Ua)/q
    dU = qVba
    Vba = Vb - Va

    V = (1/(4pieo))*(Q/r)

    3. The attempt at a solution

    I don't even know where to begin with this question.
     
    Last edited: Jul 20, 2010
  2. jcsd
  3. Jul 20, 2010 #2
    Where is your attempt at solving the problem? What about relevant equations?
     
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