# Acceleration of Ion Seperation

At the point where they leave the plates, they deviate by 0.25cm from the center, 50 cm (horizontal) later they got an additional 5 cm vertical deflection.
At least in the toy model discussed so far.
Well the vertical velocity for the other object Is 10 m/s, right? It makes sense since both object are separated by a vertical acceleration of the same magnitude. So by taking the ratio of velocity components of the first object,

100/1000=.1

Multiply it by the horizontal velocity component of the second object to get its vertical velocity component. .1 * 100 = 10

Can I do that?

OK so I found the deflection of the second object which is .25m.

The difference is -.197m. Is this correct?

Last edited:
mfb
Mentor
It would be, but your capacitor is not that large.

Yes you can take the ratio, and indeed the deflection will be 10 times the other value.

You have one beam that is deflected 10 times more than the other one. The difference between the two is 2 cm. What is the deflection of beam 1 and beam 2? Note: this question is completely independent of everything done so far.