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Well the vertical velocity for the other object Is 10 m/s, right? It makes sense since both object are separated by a vertical acceleration of the same magnitude. So by taking the ratio of velocity components of the first object,At the point where they leave the plates, they deviate by 0.25cm from the center, 50 cm (horizontal) later they got an additional 5 cm vertical deflection.

At least in the toy model discussed so far.

100/1000=.1

Multiply it by the horizontal velocity component of the second object to get its vertical velocity component. .1 * 100 = 10

Can I do that?

OK so I found the deflection of the second object which is .25m.

The difference is -.197m. Is this correct?

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