Acceleration of slab

  • Thread starter tebes
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  • #1
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Homework Statement


A slab of mass m1 = 18 kg rests on a frictionless floor, and a block of mass m2 = 12 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.30, and the coefficient of kinetic friction is 0.20. A horizontal force ,F of magnitude 58 N begins to pull directly on the block. What are the accelerations of (a) the block and (b) the slab?


Homework Equations





The Attempt at a Solution


Attempts for (a)
m1*a= F - fk
Solved for a.
I got it right.

Attempts for (b)
It's sliding (F > Fs) and there is no friction between floor and the slab.
I assumed the fk is pulling the slab. I put it in this way :
m2*a = fk.
Solved for a. But my answer is wrong.

fk = magnitude of kinetic friction between block and slab.
I would guess the equation for my (b) or my assumption is wrong.
 

Answers and Replies

  • #2
PhanthomJay
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Looks right to me. Did you check your math and value for fk?
 
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  • #3
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Looks right to me. Did you check your math and value for fk?
I just checked it. It was right. Thank you for checking, phantomjay.
 

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