Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Introductory Physics Homework Help
Acceleration of two blocks connected by a pulley
Reply to thread
Message
[QUOTE="Esoremada, post: 4520316, member: 286304"] [PLAIN]http://puu.sh/4DtNc.png[/PLAIN] I solved this question, but I don't understand why this worked. I feel like for the final line in my solution it should just be divided by M1, not the combined mass of both blocks. Isn't this synonymous with just M1 being pulled up the ramp by a guy at the top pulling with a force of 2.91*9.8 N? I thought I made an equation for the net force of just M1. The tension in the rope is 2.91*9.8, the friction is 3.19113*9.8*cos(18.5)*0.396, the gravity component pointing down the ramp is 3.19113*9.8*sin(18.5). So why does the mass of M2 have any place in solving for the acceleration of M1? I feel like it should just be. [2.91*9.8 - 3.19113*9.8*sin(18.5) - 3.19113*9.8*cos(18.5)*0.396] / (3.19113) [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Introductory Physics Homework Help
Acceleration of two blocks connected by a pulley
Back
Top