- #1

- 5

- 0

Here's what I've done:

I thought a=g(sinTheta)

Which gives me

a = 9.81(sin34)

a = 5.486 m/s2,

which isn't right. What am I doing wrong?

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- Thread starter RingWraith2086
- Start date

- #1

- 5

- 0

Here's what I've done:

I thought a=g(sinTheta)

Which gives me

a = 9.81(sin34)

a = 5.486 m/s2,

which isn't right. What am I doing wrong?

- #2

jamesrc

Science Advisor

Gold Member

- 476

- 1

[tex] F_{\rm net} = ma = mg\sin\theta - \mu mg\cos\theta [/tex]

Solve for a (you'll see that m cancels out) and then use kinematics to get the speed part.

- #3

- 5

- 0

- #4

jamesrc

Science Advisor

Gold Member

- 476

- 1

Originally posted by RingWraith2086

If only I did... Well, I'm glad I knew enough to help you here. It's also good to hear your willing to help when you can too. Keep up the good work.

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