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Acceleration plus velocity question? please help?

  1. Oct 13, 2009 #1
    Kirk and andrew are at opposite ends of a hallway stretching 29.0 m. Andrew accelerates from REST towards kirk at a constant rate of 0.18m/s^2. K irk walks towards andrew at a constant veloctiy of 3.0m/s. HOw much time elaspes before kirk and andrew high five".

    kirk
    v1= 3.0 m/s
    acc= 0 m/s^2
    distance (K)=?
    time passed =?

    andrew
    v1= 0 m/s
    time passed =?
    acc= 0.18 m/s^2
    distance= 29m -d(k)

    i then got an equation for kirk which was delta d= Vavg/ time

    and andrews was d=v1(delta)T+1/2(acc)(time^2)
    ^ ^ ^
    cancels cuz v1=0

    then i subbed d=29m-d(K) and got

    29-D(of kirk) = 1/2(acc)(time^2)

    i dont know what to do after??? any help????????? or if im doing it right at all please help!
     
  2. jcsd
  3. Oct 13, 2009 #2
    Good set up. You have the right distance formulas for both. Solve andrew's distance formula in terms of D then set both distance formulas equal to each other and you should find a time t that they intersect or meet up.

    (You will find that Andrew's distance = 29 - 1/2at^2)
     
  4. Oct 13, 2009 #3
    oooo ok thanks, now i understand the rest :smile:
     
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