A motorist drives along a straight road at a constant speed of 15.0m/s. Just as she passes a parked motocycle police officer, the officer starts to accelerate at 2.00m/s^2 to overtake her. Assuming the officer maintains this acceleration, (a) determine the time it takes the police officer to reach the motorist. Also find (b) the total displacement as he overtakes the motorist. Here's what I did: Vf=Vi+at 15=0+2t t=7.5s d=vt d=15*7.5 d=112.5 so I did a graph of: y=2x^2 and y=15x+112.5 I found when 2x^2=15x+112.5 to be x=12.1 y=294.5 So, the time it took is 12.1s and the displacement is 294.5m Is this correct?