# Acceleration problem

1. Jul 22, 2009

### jeff1evesque

Statement;
The tangential acceleration and normal acceleration is given as follows:
$$\vec{a_{T}} = \frac{4cos(2t)sin(2t)}{1 + 2sin^{2}(2t)} \cdot (\hat{x} - sin(2t)\hat{y} + sin(2t)\hat{z}), \vec{a_{N}} = - \frac{2cos(2t)}{1 + 2sin^{2}(2t)} \cdot (2sin(2t)\hat{x} + \hat{y} - \hat{z})$$ (#0)

Find the magnitude of the tangential and normal acceleration components (given above).

Solution/Attempt:
The solution for the tangential and normal magnitudes are given by the following,
$$\vec{a_{T}} = \frac{4cos(2t)sin(2t) }{\sqrt{1 + 2sin^{2}(2t)}}, \vec{a_{N}} = \frac{2\sqrt{2}cos(2t)}{\sqrt{1 + 2sin^{2}(2t)} }$$ (#1)

I mean if we had to solve for the magnitude of some vector $$a = 3\hat{x} - 33\hat{z},$$ then we say,
$$|a| = \sqrt{3^{2} + (-33)^{2}}$$. How would we apply this to our equation (#0) to get equation (#1)?

Thanks,

JL

Last edited: Jul 22, 2009
2. Jul 22, 2009

### rock.freak667

Re: Acceleration

$$|a\hat{x} + b\hat{y} + c\hat{z}| = \sqrt{a^2+b^x+c^2}$$

that's all there is to it.