A bike accelerates at 1m/s^2 from rest. (0 meters per second) After 10 seconds a car accelerates at 2m/s^2 from rest.
When are they going to meet, and where?
Right. So with this third formula, since you know the acceleration of the vehicle, you know how far it has travelled at any time. (Meaning that if you substitute a specific time value into the equation, you can calculate the distance travelled at that time).Oh, i didn't know about that sorry.
Well they indeed start from the same location.
I have been trying to solve this problem for the last 25 minutes but I can't find a soultion. I have been trying with these formulas:
Final Velocity = (Acceleration)(Time)
Distance = (Final Velocity/2) Time
Distance =(Acceleration x Time^2)/2
Final Velocity^2 = 2(Acceleration)(Distance)
Not necessarily. The easiest way to solve this problem is to start at the instant the car begins to move. That's t = 0. This means that, at t = 0, the bike has some initial position (50 m) and some initial velocity (10 m/s). You can use those in the equation for the distance of the bike vs. time.(The formulas include Starting Velocity, but as it is ZERO, I just ignored them;
If we are both at the starting line of a race and I start running first, and then you start running later, but you're going faster, then you are going to catch up to me. At the point when you catch up to me, our distances from the starting line are the same, right? In other words, our positions are equal. The same thing is true when car catches up to the bike. The two vehicle's positions are equal at that instant.That's maybe what I'm missing, what is that fact?