Acceleration problems

  • #1

Homework Statement


I) A car slows down from 23 m/s to rest in a distance of 80 m. What was its acceleration, assumed constant?

II) A car slows down uniformly from a speed of 26.0 m/s to rest in 5.50 s. How far did it travel in that time?

Homework Equations



what am i doing wrooong? am i using the right formula?

The Attempt at a Solution


I) I used this formula: a=Vf-Vi/tf-ti but the problem doesn't give me time so it didn't work

II) I used the same formula ^^ 0-26.0/0-5.50=4.72 is not the answer
 

Answers and Replies

  • #2
179
0
Well, you can find the time it took to travel 80m using Vavg and then find the acceleration. Or v^2 = vo^2 + 2ax
For the second part, you need to find distance not acceleration. Which is equal to Vavg*t
 
  • #5
Ok, I got problem # II.

I still don't understand # I...
So I find the Vavg = (0+23)/2 = 11.5
am I right here?
Then I guess I plug that into the formula:
11.5^2=0^2+2 a (80?) >> I don't know what's my X

Help!!
 
  • #6
kuruman
Science Advisor
Homework Helper
Insights Author
Gold Member
9,132
2,514
Since the time is not given, use the kinematic equation that relates acceleration, displacement and the squares of the final and initial velocity.
 
  • #7
Since the time is not given, use the kinematic equation that relates acceleration, displacement and the squares of the final and initial velocity.
that's what I'm doing and I'm not getting the right answer
v^2 = vo^2 + 2ax

0=23^2+2a(80)
0=689a
 
  • #8
Integral
Staff Emeritus
Science Advisor
Gold Member
7,200
56
that's what I'm doing and I'm not getting the right answer
v^2 = vo^2 + 2ax

0=23^2+2a(80)
0=689a
How did you combine those factors? The first does not have an a in it so cannot simply be added.
 
  • #9
kuruman
Science Advisor
Homework Helper
Insights Author
Gold Member
9,132
2,514
Your algebra is wrong.

0 = 232+2*a*80 is OK. It's the next step that is incorrect. Doing the number multiplications gives

0 = 529 + 160*a

You can't add 529 and 160*a to get 689*a !! To get 689*a you need to add 529*a + 160*a, which is not what you have here.

Instead, you say

160a = -529

a = -529/160 m/s2
 
  • #10
ok,
0(final)=23^2(initial) + 2 a (80)
I got the 23 ^2 which is 529
then I multiplied 80 * 2 =160
then I added 529 +160 =689
 
  • #11
oooooooh ok,
thanks a lot kuruman!! I really appreciate it.
 

Related Threads on Acceleration problems

  • Last Post
Replies
1
Views
670
  • Last Post
Replies
2
Views
696
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
9
Views
1K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
7
Views
2K
  • Last Post
Replies
14
Views
1K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
1
Views
718
  • Last Post
Replies
1
Views
1K
Top