A car is travelling at 19.0 m/s [W] when it enters a curved portion of the track and experiences an average acceleration of 0.270m/s^2 [N] for 62.0 seconds. Determine the velocity of the car after this acceleration. Include a vector diagram. -v1= 19.0m/s [E] a= 0.270 m/s^2 [N] delta t= 62.0 s v2= ? so i thought that u can solve this by just plugging into the formula a= v2-(-v1)/ delta T which gives me 36 m/s as v2, but it also says to use a vector diagram, which i get another answer of 25.3 m/s? HELP?