1. The problem statement, all variables and given/known data A helicopter rises vertically with a constant upward acceleration of 0.34 m/s2 . As it passes an altitude of 20 m, a wrench slips out the door. 2. Relevant equations How soon does the wrench hit the ground? At what speed does the wrench hit the ground? 3. The attempt at a solution I have attempted to solve for the initial velocity of the wrench (3.6m/s), and from that I was able to solve for time using x=x(0) +V(0)t+1/2at^2 From this I get that the time is then 2.4s. I am a bit confused tho, as first I know this is wrong. And second whether we are calculating the time of the item travelling up and then back to the ground again. For the second part of the question, I know I need to find the final velocity of the wrench on its way down for this i would use v2^2=v1^2+2AD So for this one I have been getting 19.8m/s. But again I am not sure if this is the correct answer. If someone can please lend a hand on this that would be perfect. Thanks in advance!