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Accerlation distance etc

  1. Feb 17, 2007 #1
    bascially, not techinally a question, but some basic theory i need to know for the batch of qu's.

    basically, i need to know how to find the distance travelled by something using a speed/time graph. i know this is area under it (curvey accerlation then constant speed then curvey retardation). so i what i though i'd do is split the graph into, accel., constant v, and retard. now i know how to find the distance travelled during constant v. but i not sure how to do with accerlation and retardation.

    i know the accerlation to be 6.62m/s^2 for 2.9s and the retardation to be -1.2m/s^2 for 1s, or i 'think' it can be written as 1.2m/s^-2 ???

    anyways, can someone please explain how i would find the distance travelled please :D and say if im doint he wrong way too. thnx
     
  2. jcsd
  3. Feb 17, 2007 #2

    Hootenanny

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    Is it a requirement of the problem that you are to solely use the s/t graph? Perhaps a kinematic equation would be more appropriate here. Have you met such equations before?
     
  4. Feb 17, 2007 #3
    dont think i have, i'm only 16 and are doing the exam all other 16 year olds are doing.

    well providing i could use this 'kinematic equation' i dont see why i shouldn't

    i'm not exactly sure how i would find the distance travelled solely using the s/t time graph :S

    thnx
     
  5. Feb 17, 2007 #4

    Hootenanny

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  6. Feb 17, 2007 #5
    no sorry, that above my level, so are there any other ways then?

    thnx for all the help
     
  7. Feb 17, 2007 #6

    Hootenanny

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    I suppose you could approximate the graph as a trapezium or various other shapes and calculate an approximate area; but I'm not sure. Perhaps someone with more knowlage of GCSE level questions could chip in here...

    Just one more point;
    [tex]-1.2m/s^2 \neq 1.2m/s^{-2}[/tex]
     
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