Hypochlorous acid, HOCl, is a weak acid in water. The Ka expression for HOCl is shown below: [H3O+][OCl-]/ [HOCl]= 3.2 X 10^-8 1) write a chemical equation showing how HOCl behaves as an acid in water. i got: HOCl + H2O = H3O + OCl 2) calculate the PH of a 0.175 M solution of HOCl. i got: HOCl + H2O = H3O + OCl Initial: 0.175 0 0 0 Change: -x -x +x +x Equilibrium: 0.175-x -x +x +x am i doing it right? how do u calculate the PH from x? 3) write the net ionic equation for the reaction between the weak acid HOCl and the strong base NaOH. I got: HOCl + NaOH = H3O +Na +OH is it right? 4) In an experiment, 20 mL of 0.175 M of HOCl is placed in a flask and titrated with 6.55 mL of 0.435 M NaOH. A)Calculate the number of moles of NaOH added. I did: (6.55/1000) x (0.435 M) = 0.0025 B) Calculate [H3O+] in the flask after the NaOH has been added. where do i start? i dont get what the question is asking. C) Calculate [OH-] in the flask after the NaOH has been added. where do i start? i dont get what the question is asking. thank you.