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Hey guys, I'm having a problem with this question;

Malonic Acid, C

Since Malonic Acid is diprotic, I think the chemical equation is;

C

I knw that if the equation is true, the stoichiometric ratio of NaOH : C

Hence, the mass of Malonic Acid required would be 0.035mol x molar mass. However, how did the 30mL fit in? Thanks.

Malonic Acid, C

_{3}H_{4}O_{4}, is a diprotic acid. How many grams of it are in a 30mL sample that requires 35mL of 2M NaOH for complete neutralization?Since Malonic Acid is diprotic, I think the chemical equation is;

C

_{3}H_{4}O_{4}+ 2NaOH --> Na_{2}C_{3}H_{2}O_{4}+ 2H_{2}O .I knw that if the equation is true, the stoichiometric ratio of NaOH : C

_{3}H_{4}O_{4}is 2 : 1 so the number of moles of Malonic Acid is 0.5 x (2 x (35 / 1000)mol = 0.035mol .Hence, the mass of Malonic Acid required would be 0.035mol x molar mass. However, how did the 30mL fit in? Thanks.

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