1. The problem statement, all variables and given/known data what is the H, Oh , ph and poh for a 0.048 mol/l solution of benzoic acid? C6H5COOH 2. Relevant equations Ph +poh=14 Ph=-log(h30+) H30=10^-ph 3. The attempt at a solution I thought maybe u need to separate benzoic acid into its ions and then use the molar ratio to find the concentration of H? but what does that break down into?