1. The problem statement, all variables and given/known data One organ pipe open on both ends and one organ pipe open at one end and closed at the other are tuned on the same fundamental tone with frequency f = 264 Hz. a)How long is each pipe? b) Determine the first three harmonics of each pipe. c) There is an organ pipe open at both ends, where the frequencies of three neighbo- ring harmonics are 466:2 Hz, 582:7 Hz and 699:2 Hz. To which harmonics do this frequencies belong? d) How long is this pipe? Velocity c = 343 m/s. whats is the basic difference if an organ pipe in open on both ends or one end closed ? To find the length in part d) should i apply the same relationship ? 2. Relevant equations 3. The attempt at a solution I tried like , A) Since Wavelength * Freq = Speed Therefore Wavelength = Speed / Freq Wavelength = 343 m.s / 264 Hz Wavelength =1.299m For Open Pipe: L = 1/2 (wavelength) L = 0.649 meter For Closed Pipe: L= 1/4 Wavelength L = 0.3247 meter B) Open Pipe Closed Pipe L = 1/2 Wavelength L = 1/4 Wavelength L= 2/2 Wavelength L = 3/4 Wavelength L= 3/2 Wavelength L = 5/4 Wavelength C) Should I apply fn = n f1 if yes so is the f1 = 264 Hz ???