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Problem:

For A=5<36.9 and B=5<53.1

a)Calculate the sum A+B

b)Calculate the difference A-B

c)Calculate the product AB in both polar and rectangular forms.

d)Calculate the quotient A/B in both polar and rectangular forms.

e)If A = 3 +j4, compute 1/A in both polar and rectangular forms.

a) A+B->

tan([tex]\theta[/tex])=v2/v1 =

tan([tex]\theta[/tex])=5/5

([tex]\theta[/tex])= acrtan(1)

([tex]\theta[/tex])= (pi/4)

Vr=V1^2 +V2^2 = 5^2 + 5^2 = 50V^2

Vr=sqrt(50V^2)

Vr= 5sqrt(2)V

thus, A+B= 5sqrt(2)< (pi/4)

b) A-B -> not certain of the difference between adding and subtracting phasors...?

tan([tex]\theta[/tex])=v2/v1 =

tan([tex]\theta[/tex])=5/5

([tex]\theta[/tex])= acrtan(1)

([tex]\theta[/tex])= (pi/4)

Vr=V1^2 - V2^2 = 5^2 - 5^2 = 0

Vr=0

thus, A+B= 0(pi/4)?? This means 0 voltage?

c) A*B

V1<([tex]\theta[/tex])1 * V2<([tex]\theta[/tex]) = V1V2 < (([tex]\theta[/tex])1 + ([tex]\theta[/tex])2)

5*5< (36.9+53.1) = 25<90

25<90 in polar?

d) A/B ->

[V1<([tex]\theta[/tex])1]/[V2<([tex]\theta[/tex])2] = (V1/V2) <([tex]\theta[/tex])1 -([tex]\theta[/tex])2

5/5 < (39.6 - 53.1) = 1< -16.2

e) A = 3 +j4, compute 1/A ->

not sure how to get started here...