- #1

TheBeesKnees

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## Homework Statement

During an adiabatic process, the temperature of 5.50 moles of a monatomic idea gas drops from 495 C to 215 C. For this gas, find (a) the work it does, (b) the heat it exchanges with its surroundings, and (c) the change in its internal energy

## Homework Equations

I know work is P(delta V)

PV1=nRT1 and

PV2=nRT2 so if I subtract to get the change,

P(deltaV)=nR(delta T)

P(deltaV)=5.50(8.31)(280)

P(deltaV)= 12797.4 Joules.

But my textbook says this isn't the answer.

Where did I go wrong?

I know the answer for b is zero, since that's the definition of an adiabatic process