Adiabatic process

1. The problem statement, all variables and given/known data
1 kg of H20 goes through a reversible adiabatic proces from 220kPa, 200C to 50C in the final state. What is the pressure final and volume final?

Assume S1=s2


2. Relevant equations

Conservation of Energy

3. The attempt at a solution

Found S to be 7.5080, was thinking I could find this relating to 30°C, but missing something.

 

T_2 = T_1 \left( \frac{P_2}{P_1} \right)^{\frac{\gamma-1}{\gamma}}

Found that, but dont really know what the gammas represent?

 

Wow, I was way over complicating that, thanks so much RTW69!!!

Then I took the specific volume X the mass of the water and got the volume (just in case someone looks at this in the future).