A fixed quantity of an ideal monatomic gas (γ = 5/3) is being taken around a cycle p1 = 10 atm V1 = 2 L T1 = 370 K V2 = V3 = 15 L p2= 4/3 Here's what's happening: During the isothermal process, the gas expands while in contact with a large heat reservoir, so its temperature remains constant (T2 = T1). During the constant volume (isochoric) process, the gas is cooled from T2 to T3 by putting it in contact with a reservoir at temperature T3. (This is an irreversible process.) During the adiabatic process, the gas is compressed while isolated from outside heat sources, so no heat flows. Work is done on the gas to compress it. The temperature rises from T3 to T1, so the gas has returned to its original state. What is the pressure of state 3? -I can't get this. I have p1T1^(5/3) = p3T3^(5/3), but that is 1 equation with 2 variables. What else can I uses? I don't know the work in this phase either.