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**1. Homework Statement**

The slope of an adiabatic curve will be equal to r times the slope of an isothermal curve only when we use the ideal gas equation

**2. Homework Equations**

**3. The Attempt at a Solution**

Adibatic process, P(V)^g = constant

Differentiating w.r.t V

(V)^gdp/dv+[g(v)^g-1]P=0

dp/dv= -[g(V)^g-1]P/v^g

dp/dv= -g P/V

Slope of an isothermal curve using P=nRT/V is -nRT/V^2 = -P/V

Therefore slope Adiabatic = g times slope isothermal

Am i Correct ??

Can we use vander waal eqn also ?