1. The problem statement, all variables and given/known data The slope of an adiabatic curve will be equal to r times the slope of an isothermal curve only when we use the ideal gas equation 2. Relevant equations 3. The attempt at a solution Adibatic process, P(V)^g = constant Differentiating w.r.t V (V)^gdp/dv+[g(v)^g-1]P=0 dp/dv= -[g(V)^g-1]P/v^g dp/dv= -g P/V Slope of an isothermal curve using P=nRT/V is -nRT/V^2 = -P/V Therefore slope Adiabatic = g times slope isothermal Am i Correct ?? Can we use vander waal eqn also ?