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mkbh_10
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Homework Statement
The slope of an adiabatic curve will be equal to r times the slope of an isothermal curve only when we use the ideal gas equation
Homework Equations
The Attempt at a Solution
Adibatic process, P(V)^g = constant
Differentiating w.r.t V
(V)^gdp/dv+[g(v)^g-1]P=0
dp/dv= -[g(V)^g-1]P/v^g
dp/dv= -g P/V
Slope of an isothermal curve using P=nRT/V is -nRT/V^2 = -P/V
Therefore slope Adiabatic = g times slope isothermal
Am i Correct ??
Can we use vander waal eqn also ?