Proving Cluster Point Existence in E: Insights from Advanced Calculus

In summary, a is a cluster point of E if and only if the set (E intersection (a-r,a+r))\{a} is nonempty for each r > 0. A point a is considered a cluster point of a set E if there are infinitely many points in (a-r,a+r) for every r > 0. To prove that a is a cluster point, one can start by proving that if the set (E intersection (a-r,a+r))\{a} is nonempty for each r > 0, then there is at least one point in (a-r,a+r) for every r > 0. This can be extended to show that there are multiple points in (a-r,a
  • #1
ccox
4
0
Prove that a is a cluster point of E if and only if the set (E intersection (a-r,a+r))\{a} is nonempty for each r > 0.

I have the forward implication done but the backwards implication is giving me some trouble. Could you explain it to me.
 
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  • #2
What is your definition of "cluster point?"
 
  • #3
A point a in the reals is called a cluster of E if (E intersection(a-r,a+r) contains infinitely many points for every r>0.
 
  • #4
Well, if you're having trouble proving something complicated, try proving something simple first.

"infinitely many points" is a lot... maybe you can prove that

if the set (E intersection (a-r,a+r))\{a} is nonempty for each r > 0​

then

(E intersection(a-r,a+r) contains one point for every r>0.​

Then what about two points? Three points?
 
  • #5
If there are only finitely many points in (a-r,a+r)-{a}, then there is some point closest to a, and so...
 

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