- #1

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[∂δ]/[/∂t] = [ρg]/[/μ] δ^2 [∂δ]/[/∂z].

The solution for this is:

δ(z, t) = √[μ z]/[/ρg t].

I don't really understand how the PDE became like this. If you could show the step-by-step solution, I would really, gladly appreciate it. Thank you :)

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- Thread starter sagigirl
- Start date

- #1

- 1

- 0

[∂δ]/[/∂t] = [ρg]/[/μ] δ^2 [∂δ]/[/∂z].

The solution for this is:

δ(z, t) = √[μ z]/[/ρg t].

I don't really understand how the PDE became like this. If you could show the step-by-step solution, I would really, gladly appreciate it. Thank you :)

- #2

berkeman

Mentor

- 59,468

- 9,591

[∂δ]/[/∂t] = [ρg]/[/μ] δ^2 [∂δ]/[/∂z].

The solution for this is:

δ(z, t) = √[μ z]/[/ρg t].

I don't really understand how the PDE became like this. If you could show the step-by-step solution, I would really, gladly appreciate it. Thank you :)

Welcome to the PF.

Is this for schoolwork?

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