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Can someone help me with this, I need to prove that a flat vortex sheet of strength [tex] \gamma(s) [/tex] at an angle of attack [tex] \alpha [/tex] with the horizontal and has a [tex] p_{2} - p_{1} = \rho V_{\infty} \gamma cos(\alpha) [/tex]
I just need to mathematically manipulate 2 formulas, namely the following two:
[tex] \gamma = u1 - u2 [/tex] where u1 and u2 are the tangential flow velocities above and below the vortex sheet, respectively. I know that [tex] V_{\infty} [/tex] is coming in parallel to the horizontal
Also, I need to use the Bernuolli equation: [tex] p_{1} + \frac{1}{2}\rho V_{1}^2 = p_{2} + \frac{1}{2}\rho V_{2}^2 [/tex]
this should be easy but i can't figure it out..any help is appreciated!
I just need to mathematically manipulate 2 formulas, namely the following two:
[tex] \gamma = u1 - u2 [/tex] where u1 and u2 are the tangential flow velocities above and below the vortex sheet, respectively. I know that [tex] V_{\infty} [/tex] is coming in parallel to the horizontal
Also, I need to use the Bernuolli equation: [tex] p_{1} + \frac{1}{2}\rho V_{1}^2 = p_{2} + \frac{1}{2}\rho V_{2}^2 [/tex]
this should be easy but i can't figure it out..any help is appreciated!