- #1

- 10

- 0

If the constant is taken as 10km/s (just for the sake of easiness), how can this be figured out using calculations?

I appreciate any help!

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- #1

- 10

- 0

If the constant is taken as 10km/s (just for the sake of easiness), how can this be figured out using calculations?

I appreciate any help!

- #2

- 920

- 0

the current value of Hubble constant is 71km/s/Mpc,now if you want to calculate the Hubble time, that is the time that have passed since Big bang, you do:

T=10^{12}/H

where H is the Hubble constant, the result gives the Hubble time in years. If I put 71 in H, if gives 14 billion of years

From the formula you can see that the Hubble constant diminish in value with time, as the Hubble time augments

T=10

where H is the Hubble constant, the result gives the Hubble time in years. If I put 71 in H, if gives 14 billion of years

From the formula you can see that the Hubble constant diminish in value with time, as the Hubble time augments

Last edited:

- #3

- 4

- 0

v=H*X ---- X - Current radius of universe.

So the time of that particle to reach there(age of universe) is

X/V

Which is 1/H

That's it.. Age of universe is Inverse Of H..

This is the most silliest way of explaining it..

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