- #1

- 10

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If the constant is taken as 10km/s (just for the sake of easiness), how can this be figured out using calculations?

I appreciate any help!

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- #1

- 10

- 0

If the constant is taken as 10km/s (just for the sake of easiness), how can this be figured out using calculations?

I appreciate any help!

- #2

- 841

- 1

It depends on which model of the universe you're using. e.g., if you take a simple matter-dominated Friedmann cosmology with zero cosmological constant, you end up with the age of the universe equalling two-thirds of the reciprocal of the Hubble constant. You work out formulas from this from the Friedmann equations for the evolution of such a universe (which are in turn derived from the Einstein field equation of general relativity). See, for example:

http://itss.raytheon.com/cafe/qadir/q1626.html

http://itss.raytheon.com/cafe/qadir/q1626.html

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- #3

- 10

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Thankyou for your help but what you gave me is a bit over my head.

"I have been given the task the hubble constant is thought to be in the range 10 - 20 km/sec ^-1.

What age range does this imply for the universe?"

I am not sure where to begin...

- #4

- 841

- 1

Convert the value for the Hubble constant from km/sec/Mpc to 1/sec, and take the reciprocal. That will be roughly close to the age of the universe (in seconds); you can multiply by 2/3 if you want a Friedmann matter-dominated universe with zero cosmological constant, or multiply by some other factor if you want a different model.

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