The problem is at
I know the equation for ideal gases
pV = nRT
the definition of pressure
p = F / A
The Attempt at a Solution
The change in T is 10.
V_i = 1 cm^3
We need to first consider how the change in Temperature affects
the depth at which the bubble is.
It will goes up because the volume of the bubble increases.
The increase in Volume causes the boyonce force to increase.
Thus, the net force in f direction is zero at both depths:
F_boyonce - F_gravity = 0
g( m_Water - m_airBubble ) = 0
There is a linear relation between p and T if we assume the
situation for ideal gases.
I have apparently ignored some critical part.
It seems that the ideal Gas equation is not valid here.
The right answer is 6.2cm^3 that is (f).
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