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## Homework Statement

The problem is at

http://dl.getdropbox.com/u/175564/volumePressureTemperature.JPG [Broken]

## Homework Equations

I know the equation for ideal gases

pV = nRT

and

the definition of pressure

p = F / A

## The Attempt at a Solution

The change in T is 10.

V_i = 1 cm^3

We need to first consider how the change in Temperature affects

the depth at which the bubble is.

It will goes up because the volume of the bubble increases.

The increase in Volume causes the boyonce force to increase.

Thus, the net force in f direction is zero at both depths:

F_boyonce - F_gravity = 0

g( m_Water - m_airBubble ) = 0

There is a linear relation between p and T if we assume the

situation for ideal gases.

I have apparently ignored some critical part.

It seems that the ideal Gas equation is not valid here.

The right answer is 6.2cm^3 that is (f).

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