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Air bubble

  1. Dec 25, 2006 #1
    1. The problem statement, all variables and given/known data
    An air bubble of radius 2mm if formed at the bottom of a 3.3m deep river.Calculate radius of bubble as it comes to the surface.
    atmospheric pressure=10^5 pa and density of water=1000 kg/m^3
     
  2. jcsd
  3. Dec 26, 2006 #2
    Calculate the pressure at the bottom of the river(depth*density of liquid*graviational acceleration). Let it be P1 and the pressure above the surface of river (i.e equal to the atmosperic pressure) P2.
    Then the volume enclosed by the buble change by the factor P1/P2 (pressure is inversely proportional to the volume).
    Assuming the buble as a sphere you can easily work out the radius.
     
  4. Dec 26, 2006 #3
    Why is the pressure inversely proportional to the volume and not the surface area?
     
  5. Dec 28, 2006 #4
    At constant temperature, when pressure increases gas volume decreases(it is a general observation). Mathematically speaking, when pressure is doubled volume becomes halve of the original volume. So it is evident why volume and pressure are inversely related.

    Pressure is independent of surface area. Because pressure is defined as force exerted perpendicularly on unit area(i.e P=F/A). So pressure must not be confused with force. :confused:
     
  6. Dec 29, 2006 #5
    Thanks a lot!
     
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