Hi Everyone! Like always, thank you for helping me figure out my last physics question! I greatly appreciate the help. Here are my next questions: Q: Determine the speed at which a baseball must move in order for air resistance to be significant? A: mg = ½ * Cd * A * pair * v^2 pair = density of air (1.2kg/m^3) m = mass .1488kg g = 9.8m/s^2 A=(pi*r^2)=3.14*.115m^2=.04154 m^2 Cd = .5 (sphere) v= square root of ((2*.1488kg*9.8m/s^2)/(.5* 3.14*.04154 m^2* *1.2kg/m^3 )) v = 36 m/s or 80mph Q: If the ball were launched vertically into the air at this speed, how high will it go? A: After finding the speed in the previous question; I would use this equation to find height: KE = PE PE = mgy KE = 1/2mv^2 (½)(.1488kg)(36m/s)^2 = (.1488kg)(9.8m/s^2)y 66.122m=y Q: how long will it be air born? x = x0 + v0 *t + 1/2at^2 66.122m = 0m + 36m/s * t + -9.8m/s^2t v = I am stuck on this part and I don’t know if the rest of it is correct??? Please help!