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Air is compressd in a cylinder

  • Thread starter Karol
  • Start date
  • #1
1,380
22

Homework Statement


At the start of the compression stroke, the cylinder in a diesel motor contains 300[cm3] of air at atmospheric pressure and 270C, and at the end of the stroke the volume is 20[cm3] and manometric pressure 41[atm]. What is the temperature.

Homework Equations


$$PV=nRT\rightarrow \frac{P_1V_1}{T_1}={P_1V_2}{T_2}$$
In an adiabatic process: ##T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}##
And: ##P_1V_1^{\gamma}=P_2V_2^{\gamma}##
γ for air=1.4

The Attempt at a Solution


First i check if this is an adiabatic process by comparing the initial and final volumes and pressures:
$$T_1V_1^{\gamma-1}=1\cdot 300^{1.4}=2937$$
$$T_2V_2^{\gamma-1}=42\cdot 20^{1.4}=2784$$
So it's not, heat leaks.
So i calculate using the equation of state:
$$\frac{P_1V_1}{T_1}={P_1V_2}{T_2}\rightarrow \frac{1\cdot 300}{300}=\frac{42\cdot 20}{T_2}\rightarrow T_2=840^0K$$
Is my method true?
 

Answers and Replies

  • #2
19,957
4,109
Yes. Note that this is strictly an ideal gas problem. You didn't need to use the equations with the gammas. But, if you had, would your results have been consistent with the gamma equations?

Chet
 
  • #3
1,380
22
But, if you had, would your results have been consistent with the gamma equations?
You mean if i solved the gamma equations? i guess not since it isn't adiabatic, i don't understand the question, i think
 
  • #4
19,957
4,109
You mean if i solved the gamma equations? i guess not since it isn't adiabatic
Yes, that's what I meant, and your conclusion is correct.

Chet
 

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