In a tornado, the pressure can be 15 percent below normal atmospheric pressure. Suppose that a tornado occurred outside a door that is 195 cm high and 91 cm wide. What net force would be exerted on the door by a sudden 15 percent drop in normal atmospheric pressure? In what direction would the force be exerted?
Here lies the problem.
I do no know which formula I should be using.
I know that atmospheric pressure is about 1.0 x 10^5 N/m squared at sea level.
Which I'm inferring is what I would use for the problem.
Could someone post a formula or something?
I think that's all I would need.