When a halogenoalkane reacts with aqueous sodium hydroxide under reflux conditions, an alcohol is formed.
However, when the same halogenoalkane reacts with ALCOHOLIC sodium hydroxide under reflux, an alkene is formed (It is an elimination reaction).
Now, the problem is why does a change in solvent result in different products being formed?
2. The attempt at a solution
Alcohol is a non-polar solvent while water is a polar solvent. But how does that reason link to the question asked?