# Algebra 1 Problem.

1. Mar 18, 2007

### AznBoi

I'm confused on how to solve this problem effectively. I have solved it using my own "wierd" way. I will post my solution but please post others that may be more understandable. Thanks.

Problem: Mr. Jacobs can correct 150 quizzes in 50 minutes. His student aide can correct 150 quizzes in 75 minutes. Working together, how many minutes will it take them to correct 150 quizzes?

My solution:
150q/50m = 15/5=3x

150q/75m= 2x

2x+3x=5x=150

x=30 ..lol

2. Mar 18, 2007

### symbolipoint

Think of correcting 150 quizes as "one job". The problem description involves rates. Rate * Time = Jobs

Mr. Jacobs: 1 job per 50 minutes
student aid: 1 job per 75 minutes

Similar to rate*time=distance, these rates may be additive if Mr. Jacobs and his aid work together.

3. Mar 19, 2007

### HallsofIvy

Actually, your "weird" way is perfectly reasonable- you calculated the rate at which they correct grades: Mr. Jacobs corrects 3 quizzes per minute and his aid corrects 2 quizzes per minute. Together they correct 5 quizzes per minute.