The electron, having been held at height h0, is now released from rest. Calculate its speed v when it reaches the top plate.(adsbygoogle = window.adsbygoogle || []).push({});

I found the initial energy to be:

-q_e*E*h_0

and the final energy to be:

1/2*m*v^2+-q_e*E*h_1

And I need to solve for v, so I set the two equal to each other as per the conservation of energy thereom and solve for v, correct?

-q_e*E*h_0 = 1/2*m*v^2+-q_e*E*h_1

My problem is isolating v and cancelling/clearing up variables. My algebra is lagging a bit, admittedly. Thanks for any help.

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# Homework Help: Algebra Clarification Requested - The Fate of an Electron in a Uniform Electric Field

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