The electron, having been held at height h0, is now released from rest. Calculate its speed v when it reaches the top plate. I found the initial energy to be: -q_e*E*h_0 and the final energy to be: 1/2*m*v^2+-q_e*E*h_1 And I need to solve for v, so I set the two equal to each other as per the conservation of energy thereom and solve for v, correct? -q_e*E*h_0 = 1/2*m*v^2+-q_e*E*h_1 My problem is isolating v and cancelling/clearing up variables. My algebra is lagging a bit, admittedly. Thanks for any help.