- #1

- 5

- 0

3(x-3) + 4x+7= 5x-3

And How would I solve these Quadratic Equation:

x^2 + 7x + 12 = 0

3x^2 - 10x + 8 = 0

8y^2 + 18y = 5 = 0

Thanks.

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- Thread starter Nicholasw
- Start date

- #1

- 5

- 0

3(x-3) + 4x+7= 5x-3

And How would I solve these Quadratic Equation:

x^2 + 7x + 12 = 0

3x^2 - 10x + 8 = 0

8y^2 + 18y = 5 = 0

Thanks.

- #2

- 793

- 4

For the quadratics, try factoring. If you don't want to use that method, you can always use the quadratic formula.

Jameson

- #3

TD

Homework Helper

- 1,022

- 0

Simplify it by working out the paranthesis and put everything in x on 1 side, this should give an easy lineair equation.Nicholasw said:3(x-3) + 4x+7= 5x-3

Have you seen the quadratic formula to solve these solutions? If an equation is given in the form [itex]ax^2 + bx + c = 0[/itex], then the solutions are given by:Nicholasw said:x^2 + 7x + 12 = 0

3x^2 - 10x + 8 = 0

8y^2 + 18y = 5 = 0

[tex]x_{1,2} = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}

{{2a}}[/tex]

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