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Algebra question

  1. Oct 7, 2008 #1
    1. The problem statement, all variables and given/known data
    determine where the graph of the function f(x) = (x-4)/(x^2-7) has a horizontal tangent line.



    2. Relevant equationsused quotient rule. factored and simplified


    3. The attempt at a solutioncame up with ((x^2-7)-(2x^2-8x))/(x^2-7)^2
    then set to 0, and came up with -x^2-8x-7=0
    then to find the points where the graph has a horizontal tan line, i came up with 2 situations: -(x+7)(x+1) = -7, -1; or (-x-7)(x+1) = 7, -1. which one is right, and did i do the rest of it correctly/
     
  2. jcsd
  3. Oct 7, 2008 #2
    Have you learned limits? And do you have any rough idea how the equation of a horizontal tangent line looks like?
     
  4. Oct 7, 2008 #3
    yeah, i have learned limits, and i'm going to guess a horizontal tangent line is located wherever the slope is 0. i have seen too many of those equations though.
     
  5. Oct 7, 2008 #4
    ok then since you know what limits are, it makes life much easier.

    Then somewhere you might have learned that a function has a horizontl line if any of the following is the case

    [tex]\lim_{x\rightarrow- \infty}f(x)=a;\lim_{x\rightarrow \infty}f(x)=a[/tex] where a is any constant, and f is your given function.

    then y=a is your horizontal tangent line.
     
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