The problem statement, all variables and given/known data (x+6/x)^2-2(x-6/x)-35=0 Fine the values of x. The attempt at a solution Let y=x+6/x y^2-2y-35=0 (y-7)(y+5)=0 y=7 or y=-5 Check: x+6/x=7 x^2-7x+6=0 (x-6)(x-1)=0 and x+6/x=7 x^2+5x=0 (x+3)(x+2)=0 Therefore, x=6 or x=1 or x=-3 or x=-2 Now, my teacher says there is another way to do it. He says by expanding it, the values of x can be found through algebra. I've the the way I know, but can someone tell me how to do this other way? Thank you.