I posted this in the Homework/Coursework section, but I really don't consider it that at all because I'm working through this text on my own, and I'm a little stuck on this problem.(adsbygoogle = window.adsbygoogle || []).push({});

Fix [tex]n \in[/tex]N, and let [tex]A_n[/tex] be the algebraic numbers obtained as roots of polynomials with integer coefficients that have degreen. Using the fact that every polynomial has a finite number of roots, show that [tex]A_n[/tex] is countable. (For each [tex]m \in[/tex]N, consider the polynomials [tex]a_nx^n + a_n_-_1x^n^-^1 + ... + a_1x + a_0[/tex] that satisfy [tex]\left|a_n\right| + \left|a_n_-_1\right| + ... + \left|a_1\right| + \left|a_0\right| \leq m[/tex].)

By the way, this only deals with real roots. Complex roots are simply negligible.

So, I know a few things, but bringing the big picture together is really messing me up here. For example, I know that the sum of the absolute value of the coefficients for quadratic equations only has a certain number of solutions. So, whatever I electmto be, there will always be a finite number of solutions. Also, the number of quadratics with coefficients is less than or equal to m: this is also finite. When we multiply this fact times the number of roots, we have the number of roots of a quadratic whose absolute value sums to some value less than or equal tom.

The big problem I have is trying to generalize this statement for all [tex]A_n[/tex]. If anyone has any suggestions, this would be most helpful!

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# Algebraic Countability

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