Algebraic manipulation

  • Thread starter literacola
  • Start date
  • #1

Homework Statement



Was just wondering how this equation:

[tex](k*16*10^(-6))/d^2=(k*16e-6)/(30-d)^2[/tex]

gets manipulated to produce this result

[tex]20(3-d)^2=d^2 [/tex]

[tex]d=2[/tex]

Homework Equations





The Attempt at a Solution



I've tried manipulating it myself but it ends up with me spiraling off into pages of crap that is obviously wrong.
 
Last edited:

Answers and Replies

  • #2
40
0
Are you sure you typed that in right?

Were you trying to say this?:
(k*16*10-6)/d2 = (k*16*10-6)/(30-d)2

If so, then first you would cancel the k expressions at the top, reciprocal both sides, expand and solve for d. However, I get a different result than what you give below.
 

Related Threads on Algebraic manipulation

  • Last Post
Replies
3
Views
579
Replies
1
Views
3K
Replies
8
Views
1K
Replies
3
Views
2K
Replies
1
Views
1K
  • Last Post
Replies
19
Views
781
  • Last Post
Replies
7
Views
13K
  • Last Post
Replies
6
Views
1K
  • Last Post
Replies
15
Views
4K
  • Last Post
Replies
1
Views
2K
Top