# Algebraic manipulation

## Homework Statement

Was just wondering how this equation:

$$(k*16*10^(-6))/d^2=(k*16e-6)/(30-d)^2$$

gets manipulated to produce this result

$$20(3-d)^2=d^2$$

$$d=2$$

## The Attempt at a Solution

I've tried manipulating it myself but it ends up with me spiraling off into pages of crap that is obviously wrong.

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