# Homework Help: Algebraic manipulation

1. Apr 22, 2010

### literacola

1. The problem statement, all variables and given/known data

Was just wondering how this equation:

$$(k*16*10^(-6))/d^2=(k*16e-6)/(30-d)^2$$

gets manipulated to produce this result

$$20(3-d)^2=d^2$$

$$d=2$$

2. Relevant equations

3. The attempt at a solution

I've tried manipulating it myself but it ends up with me spiraling off into pages of crap that is obviously wrong.

Last edited: Apr 22, 2010
2. Apr 23, 2010

### jdc15

Are you sure you typed that in right?

Were you trying to say this?:
(k*16*10-6)/d2 = (k*16*10-6)/(30-d)2

If so, then first you would cancel the k expressions at the top, reciprocal both sides, expand and solve for d. However, I get a different result than what you give below.

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