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Homework Help: Algebraic manipulation

  1. Apr 22, 2010 #1
    1. The problem statement, all variables and given/known data

    Was just wondering how this equation:

    [tex](k*16*10^(-6))/d^2=(k*16e-6)/(30-d)^2[/tex]

    gets manipulated to produce this result

    [tex]20(3-d)^2=d^2 [/tex]

    [tex]d=2[/tex]

    2. Relevant equations



    3. The attempt at a solution

    I've tried manipulating it myself but it ends up with me spiraling off into pages of crap that is obviously wrong.
     
    Last edited: Apr 22, 2010
  2. jcsd
  3. Apr 23, 2010 #2
    Are you sure you typed that in right?

    Were you trying to say this?:
    (k*16*10-6)/d2 = (k*16*10-6)/(30-d)2

    If so, then first you would cancel the k expressions at the top, reciprocal both sides, expand and solve for d. However, I get a different result than what you give below.
     
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