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Here it is...

Let p:E->B be continuous and surjective. Suppose that U is an open set of B that is evenly covered by p. Show that if U is connected, then the partition of p^(-1)(U) into slices is unique.

Ok, I barely understand what it's asking me to show. Is it saying the partition of p^(-1)(U) is unique? Because I highly doubt it's that because any set can be partitioned many different ways!

I think it's saying that if we have a map p1:E->B that is continuous and surjective and that U is evenly covered by p1, then the partition p1^(-1)(U) will be the same as p^(-1)(U).

Is that it?

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# Algebraic Topology Question

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