Let {h_n} be a sequence of function defined on the interval (0,1) where(adsbygoogle = window.adsbygoogle || []).push({});

h_n(x) = (n+n)x^(n-1)(1-x)

a. find lim (n-> +oo) (integral) (from 0 to 1) h_n(x) dx.

b. show that lim (n-> +oo) h_n(x) = 0 on (0, 1)

c. Show that lim (n-> +oo) (integral) (from 0 to 1) h_n(x) dx is not equal to integral (from 0 to 1) (0 dx). What went wrong?

SOlutions:

a. lim (n-> +oo) integral (from 0 to 1) h_n(x) dx

= lim (n-> +oo) integral (from 0 to 1) (n+n)x^(n-1)(1-x) dx

=lim (n-> +oo)(n+n) integral (from 0 to 1)x^(n-1)(1-x) dx

= lim (n-> +oo)(n+n) (1/n - 1/(n+1))

= lim (n-> +oo)n(n + 1) (1/((n)(n+1))

= 1.

b. I used the n-th term test in proving this... because if the series of h_n(x) is convergent then lim (n-> +oo) h_n(x) = 0 on (0, 1). But by ratio test, h_n(x) is convergent because the limit of

a(n+1)/a(n) as n -> +oo is x, but 0 < x < 1.

c. That's the part that I got stuck... well, it seems that the statement above is true... how do I solve this?

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# All about sequence of functions

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