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**All numbers are equal :D**

heres the latest proof and it doesn't involve 0 anywhere. no term like (a-b) is involved unlike other similar proofs

-ab = -ab

=> a^2 - a^2 - ab = b^2 - b^2 - ab

=> a^2 - a(a+b) = b^2 - b(a+b)

=> a^2 - a(a+b) + (a+b)^2/4 = b^2 - b(a+b) + (a+b)^2/4

as (x-y)^2 = x^2 - 2xy + y^2,

[a - (a+b)/2]^2 = [b - (a+b)/2]^2

taking square roots,

a - (a+b)/2 = b - (a+b)/2

a = b

hence proved :D

now with all numbers having been proved equal without involving "0" anywhere, what's the need to study anything :D

just noticed, this is my 1st post here after 7 years