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All separable equations are exact?

  1. Apr 13, 2004 #1
    How can I show that the separable equation dy/dx = M(x)N(y) is also exact?

    Any ideas?

    Thanks in advance!

  2. jcsd
  3. Apr 13, 2004 #2


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    dy/dx = M(x)N(y) implies
    M(x)dx - dy/N(y) = 0
    is this equation exact?
    Last edited: Apr 14, 2004
  4. Apr 14, 2004 #3


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    Science Advisor

    Of course, that should be "M(x)dx- N(y)dy= 0".
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