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In the problem

y` (cosh^2)x - (sin^2)y = 0, y(0)=pi/2

i'm also stuck on the integration step...

my first step is

dy/((sin^2)y)=dx/(cosh^2)x

however, i don't how to integrate the right side~

y` (cosh^2)x - (sin^2)y = 0, y(0)=pi/2

i'm also stuck on the integration step...

my first step is

dy/((sin^2)y)=dx/(cosh^2)x

however, i don't how to integrate the right side~

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