On its highest setting a heating element on an electric stove is connected to an ac voltage of 240V. This element has a resistance of 29 ohms.(a) Find the power dissipated in the element.(b) Assuming that three-fourths of the heat produced by the element is used to heat a pot of water(the rest being wasted), find the time required to bring 1.9kg of water(half a gallon) at 15degC to a boil
Vmrs = V0 / square root 2
P=Vrms^2 / R
The Attempt at a Solution
Vrms= 240/sqrt2 = 170V
P= 170^2/29 = 997watts
I'm not sure how to answer part b.
I think I would use the equation:
Q=cm(T1-T2) but I don't know how to solve for time?