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Homework Help: Alternating Series Estimation Theorem

  1. Dec 27, 2004 #1
    Consider the following:

    [tex] \int _0 ^1 \sqrt{1+x^4} \mbox{ } dx = \left[ x + \frac{x^5}{2\cdot 5} - \frac{1}{2!2^2 9}x^8 + \frac{1\cdot 3}{3!2^3 13}x^{12} - \frac{1\cdot 3\cdot 5}{4!2^4 17}x^{16} +\dotsb \right] _0 ^1 [/tex]

    According to the alternating series estimation theorem, we find:

    [tex] \left| R_n \right| \leq b_{n+1} < \left| \mbox{ error } \right| \Longrightarrow \frac{1\cdot 3}{3!2^3 13} < 10^{-2} \Longrightarrow \int _0 ^1 \sqrt{1+x^4} \mbox{ } dx \approx 1 + \frac{1}{2\cdot 5} - \frac{1}{2!2^2 9} \approx 1.09 [/tex]

    The limits up there are easy to work with. So, how about if we'd had

    [tex] \int _{0.7} ^{1.5} \sqrt{1+x^4} \mbox{ } dx [/tex]

    instead? Do we need to take into account those limits when applying the alternating series estimation theorem? I mean:

    [tex] \left| R_n (x) \right| \leq b_{n+1} (x) < \left| \mbox{ error } \right| [/tex]

    Thanks​
     
  2. jcsd
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