- #1
tesla93
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The Problem:
A 4.60 kg rocket is launched directly upward from Earth at 9.00 km/s
What altitude above the Earth's surface does the rocket reach?
Relevant Equations:
v = √ (2GM/r)
The Attempt:
m = 4.60 kg
v = 9km/s = 9000m/s
G = 6.67 x 10^-11
9000^2 = 2(6.67^-11)(4.60)/r
r = 6.8 x 10-14m
I used that formula because it is for escape speed, which I think applies to this question, as it needs to be a certain height above the Earth to escape the pull and stay in orbit.
A 4.60 kg rocket is launched directly upward from Earth at 9.00 km/s
What altitude above the Earth's surface does the rocket reach?
Relevant Equations:
v = √ (2GM/r)
The Attempt:
m = 4.60 kg
v = 9km/s = 9000m/s
G = 6.67 x 10^-11
9000^2 = 2(6.67^-11)(4.60)/r
r = 6.8 x 10-14m
I used that formula because it is for escape speed, which I think applies to this question, as it needs to be a certain height above the Earth to escape the pull and stay in orbit.