"An aluminum calorimeter with a mass of 100g contains 250g of water. The calorimeter and water are in thermal equilibrium at 10.0Degree C. Two metalic blocks are placed into the water. One is a 50g peice of copper at 80.0 degree C. The other block has a mass of 70.0g and is origionally at a temperature of 100degree C. the entire system stabalizes at a final temerature of 20degree C. Determine the specific heat of the unknown sample. I know that for general cases; Q(water) = -Q(x) Where x is the substance put into the water mcdeltaT(water) = - mcdeltaT(x) My first question is: Does the fact that the calorimeter is made of aluminum affect the Q(calorimeter) part, which is Q(water) in my previous equation? If it does, any hints on how. I think I have to add the masses, but im unsure about the specific heat part. My other question is: How do I deal with two objects being put into the water? Any help is appreciated.